water and aqueous systems answer key
late the boiling point elevation of a solution with 0.2 mol of NaCl in 1 kg of water. (Kb for water = 0.512°C/m) Strategy: NaCl dissociates into 2 particles (Na⁺ and Cl⁻), so i = 2 ΔTb = i × Kb × molality = 2 × 0.512°C/m × 0.2 mol / 1 kg = 0.2048°